658=8j^2

Solution for 658=8j^2 equation:

658=8j^2

We move all terms to the left:

658-(8j^2)=0

a = -8; b = 0; c = +658;
Δ = b2-4ac
Δ = 02-4·(-8)·658
Δ = 21056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21056}=\sqrt{64*329}=\sqrt{64}*\sqrt{329}=8\sqrt{329}$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{329}}{2*-8}=\frac{0-8\sqrt{329}}{-16}
=-\frac{8\sqrt{329}}{-16}
=-\frac{\sqrt{329}}{-2}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{329}}{2*-8}=\frac{0+8\sqrt{329}}{-16}
=\frac{8\sqrt{329}}{-16}
=\frac{\sqrt{329}}{-2}
$